MATHS & REASONING BY - DR V K OMAR
Directions(1-2): In each of the following questions a number series is given. Below the series, a number along with (1), (2), (3) (4) and (5) is given. You have to complete the series following the same sequence as that of the given series. Then answer the question that follows.
Q1. 5 , 7, 10, 36, 136, 690
2 ,(1), (2) , (3), (4), (5)
What will come in place of (3)?
(a) 26
(b) 64
(c) 18
(d) 46
Ans.(c)
Sol. The series is based on the following pattern:
5 × 1 + 2 = 7
7 × 2 – 4 = 10
10 × 3 + 6 = 36
36 × 4 – 8 = 136
136 × 5 + 10 = 690
Similarly, the new series is as follows:
2 × 1 + 2 = 4 …. (1)
4 × 2 – 4 = 4 …. (2)
4 × 3 + 6 = 18 …. (3)
Therefore, the number 18 will come in place of (3).
Q2. 8, 4, 6, 15, 52.5, 236.25
4, (1), (2), (3), (4), (5)
What will come in place of (4)?
(a) 36.25
(b) 26.25
(c) 16.25
(d) 32.75
Ans.(b)
Sol. The series is based on following pattern:
8 × 0.5 = 4,
4 × 1.5 = 6,
6 × 2.5 = 15,
15 × 3.5 = 52.6,
52.5 × 4.5 = 236.25
Similarly,
4 × 0.5 = 2 …. (1)
2 × 1.5 = 3 …. (2)
3 × 2.5 = 7.5 …. (3)
7.5 × 3.5 = 26.25 . …(4)
Therefore, the number 26.25 will come in place of (4).
Directions(3-5): In each of the following questions a number is missing. Find this missing number from the following alternatives.
Q3. 512, 49, 216, 25, ?
(a) 8
(b) 27
(c) 64
(d) 36
Ans.(c)
Sol.
512, 49, 216, 25, 64
(83), (72), (63), (52), (43)
Q4. 15, 24, 42, 69, (?), 150
(a) 114
(b) 105
(c) 100
(d) 140
S4. Ans.(b)
Sol. The pattern of the number series is as given below:
15 + 9 = 24
24 + 18 (= 9 + 9) = 42
42 + 27 (= 18 + 9) = 69
69 + 36 (= 27 + 9) = 105
105 + 45 (= 36 + 9) = 150
Q5. 3, 7, 16, 32, ?, 93
(a) 53
(b) 57
(c) 54
(d) 60
Ans.(b)
Sol.
= 32 + 52
= 32 + 25 = 57
Directions(6-10): In these questions, which of the following number complete the given sequence?
Q6. 8, 24, 12, 36, 18, 54, (….)
(a) 27
(b) 108
(c) 68
(d) 72
Ans. (a)
Sol. Numbers are alternatively multiplied by 3 and divided by 2.
So, the next number = 54 ÷ 2 = 27.
Q7. 2, 6, 12, 20, 30, 42, 56, (….)
(a) 61
(b) 64
(c) 72
(d) 70
Ans.(c)
Sol. The pattern is 1 x 2, 2 x 3, 3 x 4, 4 x 5, 5 x 6, 6 x 7, 7 x 8.
So, the next number is 8 x 9 = 72.
Q8. 4, -8, 16, -32, 64, (….)
(a) 128
(b) -128
(c) 192
(d) -192
Ans.(b)
Sol. Each number is the proceeding number multiplied by -2.
So, the required number is -128.
Q9. 122 , 170 , 290 , ?
(a) 369
(b) 255
(c) 432
(d) 362
Ans.(d)
Sol. (11)2 = 121+1= 122,
(13)2= 169+1= 170
(17)2= 289 + 1= 290,
Similarly
(19)2 = 361 + 1 = 362
Q10. 2 ,3 , 8 , 63, ?
(a) 3900
(b) 3636
(c) 3968
(d) 3988
Ans.(c)
Sol. 22= 4-1= 3
32= 9-1 = 8
82= 64-1= 63
632=3969-1 = 3968
Direction (11-13): In each of these questions, a number series is given. In each series, only one number is wrong. Find out the wrong number from the given alternatives?
Q11. 32, 16, 24, 65, 210, 945, 5197.5
(a) 16
(b) 210
(c) 65
(d)5197.5
Ans.(c)
Sol.
So, wrong number is 65, it must be replaced by 60.
Q12. 6, 91, 584, 2935, 11756, 35277, 70558
(a) 35277
(b) 584
(c) 2935
(d) 91
Ans.(b)
Sol. The pattern of number series is as follows:
6 × 7 + 72 = 42 + 49 = 91
91 × 6 + 62 = 546 + 36 = 582 [584]
582 × 5 + 52 = 2910 + 25 = 2935
2935 × 4 + 42 = 11740 + 16 = 11756
11756 × 3 + 32 = 35268 + 9 = 35277
So, wrong number is 584, it must be replaced by 582.
Q13. 3601, 3602, 1803, 604, 154, 36, 12
(a) 3601
(b) 154
(c) 604
(d) 1803
Ans.(b)
Sol.
So, wrong number is 154, it must be replaced by 155.
Directions(14-15): What should come in place of question mark (?) in the following number series?
Q14. 656, 352, 200, 124, 86, (?)
(a) 97
(b) 49
(c) 67
(d) 57
Ans.(c)
Sol. The pattern of the number series is as given below:
Missing term is 67.
Q15. 4.5, 18, 2.25, ? , 1.6875, 33.75
(a) 35
(b) 25.5
(c) 27
(d) 43
Ans.(c)
Sol. The series is
× 4, ÷ 8, × 12, ÷ 16, × 20
MATHS & REASONING BY - DR V K OMAR
Directions (1-7): In each of the following questions, a number series is given with one term missing. Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.
Q1. 120, 99, 80, 63, 48, ?
(a) 35
(b) 36
(c) 37
(d) 38
Ans.(a)
Sol. The pattern is -21, – 19, – 17, – 15, …
So, missing term = 48 – 13 = 35
Q2. 6, 17, 39, 72, ?
(a) 89
(b) 94
(c) 116
(d) 123
Ans.(c)
Sol. The pattern is + 11, + 22, + 33, …
So, missing term = 72 + 44 = 116
Q3. 1, 9, 25, 49, 81, ?
(a) 169
(b) 112
(c) 121
(d) 144
Ans.(c)
Sol. The series consists of squares of consecutive odd numbers i.e. 12, 32, 52, 72, 92, ….
So, missing term = 112 = 121
Q4. 4, 6, 9, 13(1/2), ?
(a) 17(1/2)
(b) 19
(c) 20(1/4)
(d) 22(3/4)
Ans.(c)
Sol. The pattern is ×3/2. So, missing number =13(1/2)×3/2=27/2×3/2=81/4=20(1/4)
Q5. 0, 2, 3, 5, 8, 10, 15, 17, 24, 26, ?
(a) 28
(b) 31
(c) 32
(d) 35
Ans.(d)
Sol. The given sequence is a combination of two series:
I. 0, 3, 8, 15, 24, ? and II. 2, 5, 10, 17, 26
The pattern in each one of I and II is +3, +5, +7, +9, ….
So, missing term = 24 + 11 = 35
Q6. 2, 1, 2, 4, 4, 5, 6, 7, 8, 8, 10, 11, ?
(a) 9
(b) 10
(c) 11
(d) 12
Ans.(b)
Sol. The given sequence is a combination of three series:
I. 1st, 4th, 7th, 10th, 13th, terms i.e. 2, 4, 6, 8, ?
II. 2nd, 5th, 8th, 11th terms i.e. 1, 4, 7, 10
III. 3rd, 6th, 9th, 12th terms i.e. 2, 5, 8, 11
Clearly I consists of consecutive even numbers. So, the missing term is 10.
Q7. 8, 9, 8, 7, 10, 9, 6, 11, 10, ?, 12
(a) 5
(b) 7
(c) 8
(d) 11
Ans.(a)
Sol. The given sequence is a combination of three series:
I. 1st, 4th, 7th, 10th terms i.e. 8, 7, 6, ?
II. 2nd, 5th, 8th, 11th terms i.e. 9, 10, 11, 12
III. 3rd, 6th, 9th terms i.e. 8, 9, 10
The pattern in I is -1. So, missing term = 6 – 1 = 5.
Directions (8): In this question, one term in the number series is wrong. Find out of the wrong term.
Q8. 46080, 3840, 348, 48, 8, 2, 1
(a) 48
(b) 348
(c) 24
(d) 2
Ans.(b)
Sol. The correct patter is ÷ 12, ÷ 10, ÷ 8, ÷ 6, ….
So, 348 is wrong and must be replaced by (3840 ÷ 10) i.e. 384.
Directions (9-15): In each of the following questions, various terms of an alphabet series are given with one or more terms missing as shown by (?). Choose the missing terms out of the given alternatives.
Q9. B, D, F, I, L, P, ?
(a) R
(b) S
(c) T
(d) U
Ans.(c)
Sol.
Q10. Y, B, T, G, O, ?
(a) N
(b) M
(c) L
(d) K
Ans.(c)
Sol. The given sequence is a combination of two series:
I. Y, T, O and II. B, G, ?
I. Consist of 2nd, 7th and 12th letters from the end of the English alphabet,
while II consists of 2nd, 7th and 12th letters from the beginning of the English alphabet.
So, the missing letter in II is the 12th letter from the beginning of the English alphabet, which is L.
Q11. AZ, GT, MN, ?, YB
(a) JH
(b) SH
(c) SK
(d) TS
Ans.(b)
Sol.
Q12. 3F, 6G, 11I, 18L, ?
(a) 27O
(b) 25N
(c) 25P
(d) 27P
Ans.(d)
Sol.
Q13. N5V, K7T, ?, E14P, B19N
(a) H9R
(b) H10Q
(c) H10R
(d) I10R
Ans.(c)
Sol.
Q14. GH, JL, NQ, SW, YD, ?
(a) EJ
(b) FJ
(c) EL
(d) FL
Ans.(d)
Sol.
Q15. UPI, ?, ODP, MBQ, IAW
(a) SGL
(b) SHJ
(c) SIK
(d) SJM
Ans.(b)
Sol.
MATHS & REASONING BY - DR V K OMAR
1. What should come at the place of question mark (?) in the following number series?
509, 68, 429, 140, 365, ?A. 194
B. 192
C. 196
D. 195
E. 197
2. What should come at the place of question mark (?) in the following number series?
1, 12, 14, ?, 66, 142A. 40
B. 50
C. 56
D. 42
E. 38
3. What should come at the place of question mark (?) in the following number series?
2√3, 2√5, √30, √42, 2√14, ?A. 6√2
B. √60
C. 5√3
D. 3√5
E. √50
4. What should come at the place of question mark (?) in the following number series? 1, 2, 6, 3, 289, ?
A. 3172
B. 3414
C. 3192
D. 3429
E. 3439
5. What should come at the place of question mark (?) in the following number series?
8, 17, 34, 58, 88, ?
A. 130
B. 123
C. 102
D. 132
E. 120
Answers With Solution:
1. Ans. C.
Solution:2. Ans. E.
Solution:3. Ans. A.
Solution:
4. Ans. B.
Solution:
5. Ans.B.
Solution:
MATHS & REASONING BY - DR V K OMAR
1. What should come at the place of question mark (?) in the following number series?
2556, 636, 156, ?, 6A. 36
B. 72
C. 100
D. 112
E. 20
2. What should come at the place of question mark (?) in the following number series? 21, 85, 253, 509, ?
A. 506
B. 505
C. 510
D. 521
E. 511
3. What should come at the place of question mark (?) in the following number series?
19, 33, 67, 97, 147, ?
A. 193
B. 200
C. 210
D. 205
E. 199
4. What should come at the place of question mark (?) in the following number series?
49, 60, 98, 102, 133, ?
A. 139
B. 145
C. 140
D. 130
E. 120
5. What should come at the place of question mark (?) in the following number series?
318, 206, 150, ?, 108, 101
A. 130
B. 115
C. 122
D. 120
E. 132
Solution:
1. Ans. A.
Solution:
2. Ans. B.
Solution:
3. Ans. A.
Solution:
4. Ans. D.
Solution: Number Series Questions Asked- IPPB PO 2017
Ques 1) 5, 4, 7, 20, 79, ?
Ques 2)18, 9, 9, 13.5, 27, ?
Ques 3) 3, 83, 152, 209, 253, ?
Ques 4) 318, 160, 82, 44, ?
Ques 5) 500, 500, 493, 467, 404, ?
Ques 6) 22, 11, 11, 16.5, 33, ?
Ques 7) 6, 5, 9, 26, 103, ?
Ques 8) 401, 401, 394, 368, 305, ?
Ques 9) 4, 75, 136, 186, 224, ?
Ques 10)158, 80, 42, 24, ?
Ques 11) 3, 72, 129, 173, 203, ?
Ques 12) 309, 309, 302, 276, 213, ?
Ques 13) 24, 12, 12, 18, 36, ?
Ques 14) 126, 64, 34, 20, ? ,12
Ques 15) 4, 3, 5, 14, 55, ?
1) ⇒
5 ✕
1-1=44 ✕
2-1=77 ✕
3-1=2020 ✕
4-1=7979 ✕
5-1=394Ans 394 2)
⇒ 18 ✕ 0.5 = 9
⇒ 9 ✕ 1 = 9
⇒ 9 ✕ 1.5 = 13.5
⇒ 15.5 ✕ 2= 27
⇒ 27 ✕
2.5 = 67.5 answers3 )
There is pattern between the differences of the numbers given in the series.
83 - 3 =
80152 - 83 =
69209 - 152 =
57253 -209 =
44Now
⇒ 80 - 69 = -11
⇒ 69 - 57 = -12
⇒ 57 - 44 = -13
⇒ 44 -
30 = -14
30 is the answers
4 )
This questions was very easy, there was a clear pattern in series, no need to find the differences.
⇒ x0.5+1
⇒ x0.5+2
⇒ x0.5+3
⇒ x0.5+4
5 )
Again we need to find the differences between the numbers and then there was a pattern in the differences.
⇒ 0....-7....-26....-63....
-124 ⇒ 7....19....37....
61 ⇒12....18....
246)
⇒ x0.5....x1....x1.5....x2....x2.5
⇒ 33 ✕ 2.5 =
82.57)
⇒ x1-1….x2-1…x3-1….x4-1
8)
There is pattern between the differences of the numbers given in the series.
⇒ 0....-7....-26....-63....
-124 ⇒ 7....19....37....
61 ⇒ 12....18....
24 9)
+71....+61....+50....+38....+25
-10....-11....-12....-13
10 )
x0.5+1….x0.5+2….x0.5+3….x0.5+4
24 ✕ 1/2 + 3=
15 AnswerMATHS & REASONING BY - DR V K OMAR
Number Series Asked in IBPS RRB OS - V (Prelim) Exam - 06.11.2016 (1st Shift)
Directions (1-5): What should come in place of the question mark (?) in the following number series?#1.
4, 16, 26, 34, 40, ? a) 45
b) 46
c) 43
d) 55
e) 44
#2.
825, 582, 501, 474, 465,? a) 484
b) 642
c) 246
d) 462
e) 532
#3.
8, 12, 24, 60, 180, ? a) 360
b) 300
c) 630
d) 600
e) 720
#4.
3, 4, 10, 33, 136, ? a) 586
b) 685
c) 569
d) 690
e) 265
#5.
16, 17, 13, 22, 6, ? a) 31
b) 2
c) 1
d) 12
e) 13
Solutions :
1. e) 44
Solution: 4………16……….26………..34…...….40………
…….+12…..+10…..…..+8…..…...+6….…...+4
Answer: 40 + 4 = 44
2. d) 462
Solution: 825…….…..582….…..501….…..474……..465………
……..-243…...…-81………-27…….…-9…….…-3…
Answer: 465 – 3 = 462
3. c) 630
Solution: 8 x 1.5 = 12
12 x 2 = 24
24 x 2.5 = 60
60 x 3 = 180
180 x 3.5 = 630
4. b) 685
Solution: 3 x 1 + 1 = 4
4 x 2 + 2 = 10
10 x 3 + 3 = 33
33 x 4 + 4 = 136
136 x 5 + 5 = 685
5. a) 31
Solution: 16………..17……..13……....22……..6……
…...+1…........-4……....+9…….-16……(+25)
….(1 x 1)….(2 x 2)….(3x 3)….(4x4)....(5 x 5)
Answer: 6+25= 31
MATHS & REASONING BY - DR V K OMAR
Number Series Asked in IBPS RRB OS - V (Prelim) Exam - 05.11.2016 (1st Shift)
Directions (1-5): What should come in place of the question mark (?) in the following number series?
#1.
6 4 5 11 39 ?
a) 188
b) 198
c) 189
d) 199
e) 200
#2.
14 7 7 14 56 ?
a) 158
b) 184
c) 484
d) 884
e) 448
#3.
2 3 7 16 32 ?
a) 57
b) 59
c) 56
d) 60
e) 75
#4.
8 14 24 38 56 ?
a) 55
b) 65
c) 96
d) 78
e) 87
#5.
5 7 13 25 45 ?
a) 57
b) 75
c) 55
d) 77
e) 54
Answers:
1. c) 189
Solution:
6 x 1 – 2 = 4
4 x 2 – 3 = 5
5 x 3 – 4 = 11
11 x 4 – 5 = 39
39 x 5 – 6 = 189
2. e) 448
Solution:
14 x 0.5 = 7
7 x 1 = 7
7 x 2 = 14
14 x 4 = 56
56 x 8 = 448
3. a) 57
Solution:
2 + 12 = 3
3 + 22 = 7
7 + 32 = 16
16 + 42 = 32
32 + 52 = 57
4. d) 78
Solution:
8……....14….....24….......38….....56
…..+6…...+10…....+14…......+18
…….+4……...+4…......…+4…….+4
Answer: 56 + 18 + 4 = 78
5. b) 75
Solution:
5….....…7……...13…......25….......45
…....+2….....+6…......+12..….+20
…......…+4…...…+6….......+8……+10
Answer: 45 + 20 + 10 = 75
MATHS & REASONING BY - DR V K OMAR
Number Series Asked in IBPS RRB OS - V (Prelim) Exam - 04.11.2016 (1st Shift)
Directions (1-5): What should come in place of the question mark (?) in the following number series?
#1.
3 10 22 39 61 ?a) 88b) 85c) 66d) 95e) 83#2.
9 14 21 32 45 ?a) 52b) 56c) 72d) 62e) 66#3.
3 1.5 1.5 2.25 4.5 ?a) 9.5b) 11.25c) 12.25d) 10.45e) 5.5#4.
2 4 11 37 153 ?a) 771b) 661c) 551d) 441e) 221#5.
4 4 6 12 24 ?a) 58b) 42c) 40d) 42e) 44Answers:
1. a) 88Trick: difference upto two linesSolution:3…...….10…...…22……....39…......61 …..+7…….+12…….+17…….+22 ………+5…….+5……….+5 Ans: 61 + 22+ 5 = 88 2. d) 62Trick: difference of prime numbers Solution:9….14…..21…...32…......45 …+5…+7….+11......+13 Ans: 45 + 17 = 62 3. b) 11.25 Solution:3 * 0.5 = 1.5 1.5 * 1 = 1.5 1.5 * 1.5 = 2.25 2.25 * 2 = 4.5 4.5 * 2.5 = 11.25 4. a) 771Solution:2 * 1 + 2 =4 4 * 2 + 3 = 11 11 * 3 + 4= 37 37 * 4 + 5 = 153 153 * 5 + 6= 771 5. e) 44Trick: difference upto two lines Solution:4…........4......…6…......12.......…24
....+0….....+2........+6..........+12 ....…+2..........+4.........+6 Ans: 24 + 12 + 8 = 44 MATHS & REASONING BY - DR V K OMAR
Number Series Asked in IBPS PO - VI (Prelim) Exam - 27.10.2016 (1st Shift)Directions (1-5): What should come in place of the question mark (?) in the following number series?
#1.
7, 6, 8, 15, 44, ?
a) 88
b) 120
c) 159
d) 150
e) 195
#2.
16, 25, 42, 66, 96, ?
a) 120
b) 160
c) 118
d) 131
e) 130
#3.
4, 6, 9, 34, 68, ?
a) 56
b) 64
c) 161
d) 68
e) 116
#4.
7.6, 9.9, 14.5, 23.7, ?
a) 42.2
b) 42.1
c) 42.3
d) 42.4
e) 42.5
#5.
9, 5, 4, 7.5, 13, ?
a) 35
b) 26
c) 34
d) 48
e) 62
Answers:
1. e) 195
Solution:
7 x 1 – 12 = 6
6 x 2 – 22 = 8
8 x 3 – 32 = 15
15 x 4 – 42 = 44
44 x 5 – 52 = 195
2. d) 131
Solution:
+9….…..+17…..…+24……...+30….…..+35
+8…….…+7….…...+6…...…...+5
96 + 35 = 131
3. c) 161
Solution:
4 x 2 – 2 = 6
6 x 3 – 9 = 9
9 x 4 - 2 = 34
34 x 5 – 9 = 161
4. b) 42.1
Solution:
+2.3 ….. +4.6 ….. +9.2 .…. +18.4
7.6 + 2.3 = 9.9
9.9 + 4.6 = 14.5
14.5 + 9.2 = 23.7
23.7 + 18.4 = 42.1
5. a) 35
Solution:
9 x 0.5 + 0.5 = 5
5 x 1 – 1 = 4
4 x 1.5 + 1.5 = 7.5
7.5 x 2 – 2 = 13
13 x 2.5 + 2.5 = 35
MATHS & REASONING BY - DR V K OMAR
Number Series Asked in IBPS PO - VI (Prelim) Exam - 22.10.2016 (3rd Shift)
Directions (1-5): What should come in place of the question mark (?) in the following number series?
#1.
12, 6.5, 7.5, 17, 72, ?a) 356b) 82c) 185d) 292e) 584#2.
463, 220, 139, 112, ?, 100a) 101b) 100c) 104d) 103e) 102
#3.
17, 30, 21, 34, 25, ?a) 38b) 30c) 27d) 36e) 40#4.
31, 33, 40, 68, 131, ?a) 232b) 257c) 132d) 250e) 275#5.
11, 16, 34, 66, 113, ?a) 130b) 160c) 176d) 175e) 177Answers:
1. e) 584Solution:12 x 0.5 + 0.5 = 6.5 6.5 x 1 + 1 = 7.5 7.5 x 2 + 2 = 17 17 x 4 + 4 = 72 72 x 8 + 8 = 5842. d) 103 Solution:463 – 220 = 243 220 – 139 = 81 139 – 112 = 27 112 – ? = 9 ? – 100 = 3 So, ? = 112 – 9 = 103
3. a) 38Solution: 17 +13 = 30 30 – 9 = 21 21 +13 = 34 34 – 9 = 25 25 + 13 = 38 4. b) 257Solution: 31 + (13 + 1) = 31 + 2 = 33 33 + (23 - 1) = 33 + 7 = 40 40 + (33 + 1) = 40 + 28 = 68 68 + (43 - 1) = 68 + 63 = 131 131 + (53 + 1) = 131 + 126 = 257 5. c) 176Solution: MATHS & REASONING BY - DR V K OMAR
I.Find the wrong number in the following series.
1. 40 326 2946 29418 323607
1.326
2.40
3.2946
4.323607
5.29418
2. 560 1089 1725 2443 3284 4245
1.2443
2.1725
3.4245
4.3284
5.560
3. 3252 3080 2958 2876 2826
1.3080
2.2876
3.2826
4.3252
5.2958
4. 2442 1222 614 312 163 90 55.75
1.12222.3123.904.6145.163
5. 1250 1322 1452 1674 2024 2544
1.13222.16743.25444.20245.1250
II. Find the missing number in the given series.
6. 1953.125 781.25 312.5 ? 20 1.48
2.49
3.50
4.51
5.52
7. 81 87 162 504 1992 9990 ?
1.59903
2.59906
3.56895
4.59904
5.59861
8. 49 72 118 ? 394 762 1498
1.234
2.239
3.210
4.219
5.243
9. 142 143 156 193 272 417 ?
1.653
2.658
3.659
4.657
5.656
10. 118 122 158 206 356 536 ?
1.956
2.953
3.928
4.965
5.963
Solutions:
1.2946
40*8+6=326
326*9+7=294
2946*10+8=29418
29418*11+9=323607
2.1725
the difference between numbers is +23^2 ,+25^2 , +27^2 , +29^2 .......
3.3252
the difference between numbers is -(13^2+1), -(11^2+1), -(9^2+1) , -(7^2+1), -(5^2+1)
4. 90
2442/2 + 1 = 1222
1222/2 + 3= 614
614/2 + 5 = 312
312/2 + 7 =163
163/2 + 9 = 89.5
89.5/2 + 11 = 55.75
5. 1250
,
the difference between numbers is +(3^3+3) , +(4^3+4) , +(5^3+5), +(6^3+6) , +(7^3+7),
+(8^3+8)
6.50
1953.125/2.5=781.25
781.25/2.5=312.5
312.5/2.5=125
125/2.5=50
50/2.5=20
7.59904
the difference between numbers is *1+6 , *2-12, *3+18 , *4-24 ,*5+30 , *6-36
8.210
the difference between numbers is +23 , +46 , +92 , +184 , +368 ,+736
9.658
the difference between numbers is +1^3+0 , +2^3+5 ,+3^3+10 , +4^3+15 , +5^3+20 ,+6^3+25
10. 928
the difference between numbers is
+2^3-2^2
+3^3-3^2
+4^3-4^2
+5^3-5^2
+6^3-6^2
+7^3-7^2
MATHS & REASONING BY - DR V K OMAR
Number Series Asked in SBI PO Prelims Exam (Slot-I) - 02.07.2016
Directions (1-5): What should come in place of the question mark (?) in the following number series?
1. 7 5 7 17 63 ?
a) 308
b) 302
c) 309
d) 409
e) 390
2. 50 ? 61 89 154 280
a) 52
b) 51
c) 60
d) 62
e) 60
3. 17 19 25 37 ? 87
a) 47
b) 37
c) 57
d) 67
e) 75
4. 11 14 19 28 43 ?
a) 55
b) 44
c) 77
d) 88
e) 66
5. 26 144 590 1164 ?
a) 1296
b) 1182
c) 2059
d) 1182
e) 1181
Answers:
1. c) 309
Solution:
7 x 1 – 2 = 5
5 x 2 – 3 = 7
7 x 3 – 4 = 17
17 x 4 – 5 = 63
63 x 5 – 6 = 309
2. a) 52
Solution:
50..50+(1^3+1) = 52
52+(2^3+1)=61.
61+(3^3+1)=89
89+(4^3+1)=154
154 + (5^3+1) = 280
3. c) 57
Solution:
17 + 1 x 2 = 19
19 + 2 x 3 = 25
25 + 3 x 4 = 37
37 + 4 x 5 = 57
57 + 5 x 6 = 87
4. e) 66
Solution:
3….5...9...15...23
…2....4....6....8…
Answer 43+23= 66
5. b) 1182
Solution:
26 x 6 – 12 = 144
144 x 4 + 14 = 590
590 x 2 – 16 = 1164
1164 x 1 + 18 = 1182
MATHS & REASONING BY - DR V K OMAR
Number Series Asked in SBI PO Prelims Exam (Slot-I) - 09.07.2016
Directions (1-5): What should come in place of the question mark (?) in the following number series?
1. 150 102 70 46 26 ?
a) 16
b) 8
c) 10
d) 2
2. 10 14 28 52 134 ?
a) 302
b) 268
c) 300
d) 304
e) 208
3. 4500 900 90 6 ? 0.012
a) 0.3
b) 3
c) 3.33
d) 0.33
e) 3.3
4. 24 11 10 14 27 ?
a) 66
b) 70.5
c) 68
d) 66.5
e) 68.5
5. 8 7 12 33 128 ?
a) 528
b) 365
c) 653
d) 825
e) 635
Answers:
1. b) 8
Solution:
2. d) 304
Solution:
10*3 - 2= 28
14*4 - 4= 52
28*5 - 6= 134
52*6- 8= 304
3. a) 0.3
Solution:
4500/5 = 900
900/10 = 90
90/15 = 6
6/20 = 0.3
0.3/25 = 0.012
4. d) 66.5
Solution:
24*(1/2) – 1 = 11
11*(2/2) – 1 = 10
10*(3/2) – 1 = 14
14*(4/2) – 1 = 27
27*(5/2) – 1 = 66.5
5. e) 635
Solution:
8*1 – 1 = 7
7*2 – 2 = 12
12*3 – 3 = 33
33*4 – 4 = 128
128*5 – 5 = 635
MATHS & REASONING BY - DR V K OMAR
Number Series Asked in RBI Grade B Manager (Phase-I) Exam - 04.09.2016 (1st Shift)
Directions (Q.1 -5): In the following number series only one number is wrong. Find out the wrong number.
1. 18.3 20.6 16 22.9 13.7 2.2 11.4
a) 25.2
b) 18.3
c) 13.7
d) 22.9
e) 20.6
2. 9 5 6 10.5 23 61 183
a) 183
b) 10.5
c) 61
d) 5
e) 9
3. 188 154 140 132 128 126 125
a) 125
b) 154
c) 132
d) 126
e) 188
4. 2 4 11 37 151 771 4633
a) 11
b) 4633
c) 771
d) 151
e) 2
5. 391 394 399 411 431 461 503
a) 503
b) 394
c) 399
d) 431
e) 391
Solutions:
1. a) 25.2
18.3 + 2.3 = 20.6
20.6 - 4.6 = 16
16 + 6.9 = 22.9
22.9 - 9.2 = 13.7
13.7 +11.5 = 25.2
25.2 - 13.8 = 11.4
2. c) 61
9*0.5 + 0.5 = 5
5*1 + 1 = 6
6*1.5 + 1.5 = 10.5
10.5*2 + 2 = 23
23*2.5 + 2.5 = 60
60*3 + 3 = 183
3. e) 188
186 - 36 = 154
154 - 16 = 140
140 - 8 = 132
132 - 4 = 128
128 - 2 = 126
126 - 1 = 125
4. d) 151
2*1 + 2 = 4
4*2 + 3 = 11
11*3 + 4 = 37
37*4 + 5 = 153
153*5 + 6 = 771
771*6 + 7 = 4633
5. b) 394
391 + 2 = 393
393 + 6 = 399
399 + 12 = 441
441+ 20 = 431
431 + 30 = 461
461 +40 = 503
MATHS & REASONING BY - DR V K OMAR
Question 1: 353 354 351 356 349 ?
a) 348 b) 358 c) 338 d) 385 e) 340
Question 2: 1 5 13 29 ? 125 253
a) 83 b) 69 c) 61 d) 65 e) 81 ...
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